a binary string of length 10 is made up of 10 bits(e.g., 1100111100). How many such strings either with 110xxxxxxx or xx000xxxxx?
string count with A pattern or with B pattern = string count with A pattern + string count with B pattern - string count with A and B pattern. So, string count with 110xxxxxxx or xx000xxxxx = 10^7 + 10^7 - 10^5
...2003053001570400.htm 藍色的標題部分 另外還有一個類似的用法是: To have two strings to one's bow=To get one's back up =to have a means or expedient in reserve in case the one employed...
...and Chiang Kai-shek. The small colored lights strung up, some blinked on and off. On Double Ten Day...